8+3[1+2(2x-3)]=6(x+8)

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Solution for 8+3[1+2(2x-3)]=6(x+8) equation:


Simplifying
8 + 3[1 + 2(2x + -3)] = 6(x + 8)

Reorder the terms:
8 + 3[1 + 2(-3 + 2x)] = 6(x + 8)
8 + 3[1 + (-3 * 2 + 2x * 2)] = 6(x + 8)
8 + 3[1 + (-6 + 4x)] = 6(x + 8)

Combine like terms: 1 + -6 = -5
8 + 3[-5 + 4x] = 6(x + 8)
8 + [-5 * 3 + 4x * 3] = 6(x + 8)
8 + [-15 + 12x] = 6(x + 8)

Combine like terms: 8 + -15 = -7
-7 + 12x = 6(x + 8)

Reorder the terms:
-7 + 12x = 6(8 + x)
-7 + 12x = (8 * 6 + x * 6)
-7 + 12x = (48 + 6x)

Solving
-7 + 12x = 48 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
-7 + 12x + -6x = 48 + 6x + -6x

Combine like terms: 12x + -6x = 6x
-7 + 6x = 48 + 6x + -6x

Combine like terms: 6x + -6x = 0
-7 + 6x = 48 + 0
-7 + 6x = 48

Add '7' to each side of the equation.
-7 + 7 + 6x = 48 + 7

Combine like terms: -7 + 7 = 0
0 + 6x = 48 + 7
6x = 48 + 7

Combine like terms: 48 + 7 = 55
6x = 55

Divide each side by '6'.
x = 9.166666667

Simplifying
x = 9.166666667

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